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7v^2-57v+56=0
a = 7; b = -57; c = +56;
Δ = b2-4ac
Δ = -572-4·7·56
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-41}{2*7}=\frac{16}{14} =1+1/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+41}{2*7}=\frac{98}{14} =7 $
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